+ Reply to Thread
Page 6 of 10 FirstFirst 1 2 3 4 5 6 7 8 9 10 LastLast
Results 51 to 60 of 96

Thread: The Logic Gate

  1. #51
    erexere's Avatar
    erexere is offline Expert Twelever TwelevePlus
    Emerald
    erexere is on a distinguished road
    Join Date
    Jun 2005
    Location
    Springfield, Oregon
    Posts
    1,975

    Default

    I need help understanding the scope of seeking more hidden information in the morse. I feel that its multipurpose but limited to 2 or 3 applications at most. Lucid and memory bring my thoughts to the ciphertext line with JUNGE, which I will continue to wonder about....ANIMUS? I'm most unfamiliar with the subject of psychology. Lucid also makes me think of Euclid for a geometry nudge. Memory could be a hint for a simple pattern matching game like the one where you pair up cards of the same value or picture. Does this hint at a method for pairing up specific locations or letters?
    ========================

  2. #52
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    You've said something that gave me an idea that I'd like to explore.


    First, let me unpack a little about where I'm going with the Morse. I think all these clues will be matrixed so that we can extract acrostic information in the vertical axis, maintaining consistency with the decryption method and clues thus far. This is still step one: that we are now realizing nobody has ever understood before, so we need to "wrap" it, to progress beyond the entrance.


    I think when it "works", we're going to have a 98 character string. Recalling the relationship with the calendar, I think they will have to be ordered by either seniority, or with respect to certain dates i.e.:birth, death, etc. Recalling the Hydra, one of them (the mummy daddy), is symbolically decapitated, and placed under a large rock. This is the immortal one. The Hydra thus defeated has 8 Heads. Top and bottom might be "Washington" or a date (what is your position back then) and perhaps Langley or a date (your position now.) Finally, I have detected an artistic motivation in that it seems to me to be like the dedication plaque at the OHB, but in abstract terms.


    On to your stuff: When I wrote before, suggesting a lunar calendar, it wasn't completely obvious to me as to how this would help my strategy of decrypting the Morse completely to try to find "a string". As our discussion has progressed, we seem to be in complete agreement that there are two ready-made dictionaries on the deciphered panels. There is also incontrovertible evidence that dates=locations.


    Well,


    If we use a lunar calendar, we have a 13 rows representing the lunar months. If we start at the top as you mentioned with "December", we would meet at the abscissa in that "lunar month after January but before Feb". On the lower tableau, we start here and end with December on the bottom line.


    big things:


    we now have a 26 letter Y axis register, one for every letter in K4. Connect that with the playfair discussion we had last night. 26 x 28 = 728, and to this way of thinking, we have 140 characters extra: the abscissa.


    The bottom line has every letter in the alphabet, but the top does not. Some of the things you detected suggest areas within K1 that may need to be abscised and replaced with something else. You and I noted some of these trigrams and hexgrams seem like they'd fit. Perhaps so that line one has all the letters of the alphabet? What letters are missing from K1?


    Also, the Lunar calendar should call attention to eclipses. I would think the 1919 proof of Einstein's theory could find its way back into your thinking. The only problem might have been trying to cram "relativity" into it. In parallel to the "ultra simplicity" theme: When the average person thinks Einstein, they think E=MC^2 right? You had been looking for an E replacement strategy, right? Well, how about after that "date" E's now equal MCII in Latin letters, for example. MC^2 is also expressed as MC X MC = MCCX with a line over it. In Latin, A line over the top of numbers means it's like scientific notation like 121 x 10^4. In Latin it means whatever the number is multiplied by 1000.


    so,


    the Lunar calendar leaves us 140 characters short to get back to 868. E can be a lot of things if I use my imagination. K, X, Q, W, and J too.


    Wonderful things

  3. #53
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    (pressed post too quickly)


    Final parallel: you and I have both noted an indexing strategy whereby a letter=word equivalence is used. Did you notice that the Abscissa in my lunar calendar strategy matrix (26 x 2 is 140 characters, precisely the amount of unique words between the K2 and K3 dictionaries taken together?


    Now there's a WOW signal.

  4. #54
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    (OK can't stop now)


    This is amazing. If we convert to 28 char rows, we have 140 characters to get rid of but which?
    Aren't there some markings on that log? like 5 markings. 5 x 28 = 140. Get your scissors out. Regardless of how we rearrange the tableau, the marks are still indexed to their original positions, since there are indeed attached to the sculpture. I think these are lines to Abscise.


    I think I understand what Sanborn meant now, about K4. Yeah, my hand get's tired after 500 chars too, and typos, oh my god...don't get me started)

  5. #55
    erexere's Avatar
    erexere is offline Expert Twelever TwelevePlus
    Emerald
    erexere is on a distinguished road
    Join Date
    Jun 2005
    Location
    Springfield, Oregon
    Posts
    1,975

    Default

    Im curious what you think constitutes the masking of K4 or what hints of the mask's design?

    I was thinking of playfair before, but that doesnt exactly give us 2 CT for 1 PT, only in the case of null characters for double letters right?

    I'm hopeful there's a quagmire 4 involved once we sort the in between.

    Do you recall how many steps Sanborn said were involved in his cipher? Wasnt it 5 or 6? One or two of those steps being mask related?
    ========================

  6. #56
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    Yes, this is a perfect time to restate, cross-reference, and reformulate the question. Speaking for myself, I need to avoid lateral logic temporarily, so I'll try to stay away from some of the cupboard items, until we have a new straw man. I have an idea about whose II's will peek through tut's mask, but I'm trying to temporarily forget all that kind of info. Playfair too. We'll use it, but not to decrypt anything, only to orient. Sounds crazy. I'll have to explain later.


    To me, the notion of combining our separate theses about a) acrostic puzzles and b) your observation of objective links to the calendar, finds a new dimension in thinking about the tableau as a oriented by lunar, and not solar months. The single thing that made me recognize that both of our views could find a home here was that, for all intents and purposes, we are only changing from a base 12 month (row) structure, to a base 13. Nothing about your date hypothesis changes: Nov 26th is still the 331st day of the year: the dates' relative positions qua "string orientation" don't change, only their orientations on the matrix. I had a flash thought that such an approach could help explain BERLIN: although Sanborn has declared a direct correspondence between letters, and also their locations, he said nothing like "and in K4, the numbers are sequential, and in the same locations as 64-69 on the original CT tableau." If you apply deductive reasoning and logic, he almost is stating it definitively: you have to change the matrix. To this I added another of my little cupboard items I figured out in the Morse: K4 is not enciphered per ce. I think you had the same thought as I, since you immediately went to "BERLIN" after I mentioned the lunar calendar, quite possibly it was subconscious. Let's leave all this behind for a moment.


    I present a straw man, in the simplest possible terms, and number the ideas:


    1) we will take all the 868 characters we have now, and using the divisions on the petrified log to indicate, we will remove and reserve these 5 strips of 30 ish characters. After removing non-character marks like ? and X(stop) I suspect that these will leave 140 in the discard pile/728 left. 364 top and bottom.


    2) the remaining is now more properly called a string. The string will be "dealt" into a (26,2 grid- and here we may find a trap in that we need to explore all ways and not just right to left, top to bottom. I have previously deduced instructions alerting me that going back and forth (visualize traveling the long and winding road in text), and upward, may apply at some point.


    3) Once we have our grid, we need to look for a verifier. Basing my speculation again on the Morse, it might be an unmistakable word showing up acrostically, or the X's and ?'s forming a Star pattern, or something like that.


    4) First, again in reflection of my Morse observations, we may need to reorder the rows. Our secret about the calendar and the dates may be our only ability to do this according a reliable pattern. I'm seeing the date pattern emerge in the Morse right now.


    5) Once the rows are reordered, we are going to reorder the columns, until we find that unique combination that preserves our date structure, but has column 1 such that it contains each letter of the alphabet, and none more. That's our row index in the sanborn map.


    6) the step after this would be to fold the Vigenere tableau over. look through the doubles windows, and make use of that strip in row1, that up to now, has made little sense. It may be our column register.


    So, let's firm up how this transformation may take place that best sets us up to keep the rest of what we have on its feet and moving forward. Anything that can't pull its weight beyond this point has to go.

  7. #57
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    Is there any question anymore, about how the vigenere tableau awkwardly starts over again at the 26th letter? Or why Sanborn put the seemingly extraneous second indexing rows in? If we chopped off those 5 rows, on the Vigenere, how many characters would that be? Yep 140. Plus an L which symbolically tells us where to reattach it: the Log!

  8. #58
    erexere's Avatar
    erexere is offline Expert Twelever TwelevePlus
    Emerald
    erexere is on a distinguished road
    Join Date
    Jun 2005
    Location
    Springfield, Oregon
    Posts
    1,975

    Default

    I like this theory. What do you mean by "doubles" windows?
    ========================

  9. #59
    magicicada is offline Junior Twelever +1 Bronze magicicada is an unknown quantity at this point
    Join Date
    Oct 2014
    Location
    Astoria
    Posts
    112

    Default

    OK. so we're going to leave the straw man at:
    A) We need to create a grid of 26tall x 28long
    B) We don't fully understand, but we have found a link via symmetry, to the arrangement of "Heads" that I'm coming up with in my Morse work: i.e.: I'm going to end up with NATHANHALE, TJEFFERSON, ALLENDULLES JJANGLETON, etc. I think I'm seeing a means by which I order these by some sort of date. thats what I like about your calendar work. It suggests a way to do the same.
    C) We have noticed the reflection by lateral symmetry of the vigenere tableau, which if abscised from columns 1-5 (and those are 28 row columns so 5x28=140 leaving the extra index above and below for the fold), and "folded over" will exactly cover our new grid, and leave an indexing key left over in the x axis. Now we have a tableau consisting of our new grid, plus the vigenere's top row in reverse from our perspective, we have a coordinate system. We have 140 char's left over from both sides, 280 total. If we sewed these strings together, just like the morse fractions and the K3 hint, we could have a 140 character message, and the unique tableau just happens to be left over to decode it.

    Supporting this heresy:

    the map style system Sanborn's been hinting at,
    we now have the 26 letters Z-A that we needed.
    We also have ABC's, but scrambled up. Thus the need to find the proper arrangement of rows using your date research. I speculate that when folded over, we need to find doubles and replace those characters with the one's on the verso. There is, under this way of looking at it, the possibility that K4 (i.e.:the 97/9 is not encrypted at all. It's just clever masking and interruption. If I told you that the final message was produced by taking a string of bigrams, and looking them up on the tableau, and recording the letter that appeared in the coordinate location, you quickly realize that it may be the key grid that has "B E R L I N" fulfilling Sanborn's requirements, but having nothing to do at all with the string of characters that results in the solution. So after rearranging the rows we will find one and only one column arrangement that produces BERLIN anywhere on the answer key. It doesn't matter where.

  10. #60
    erexere's Avatar
    erexere is offline Expert Twelever TwelevePlus
    Emerald
    erexere is on a distinguished road
    Join Date
    Jun 2005
    Location
    Springfield, Oregon
    Posts
    1,975

    Default

    Isnt that problematic when you need the T of NYPVTT to be an I and the next T to be an N. The mask must account for that.
    ========================

+ Reply to Thread
Page 6 of 10 FirstFirst 1 2 3 4 5 6 7 8 9 10 LastLast

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts