# Thread: Binary numbers on the grid...

1. ## Binary numbers on the grid...

Hi all,
Okay, I'm pretty sure I discovered something...

Take the grid given, and for every black square, count as '0'. Every colored square, count as '1'. Read from left to right, top to bottom and get:

0010111100111110001111111

Now, break this up into 8-bit binary numbers:

00101111
00111110
00111111
1

Yes, there is one leftover. This may relate to the part of the dream "one on ending"

Notice anything about the numbers? They're exactly 1 greater than the preceeding number: 47.. 48.. 49..

Not sure of the relevance, but In ASCII that would also convert to: / .. 0 .. 1 ..

Absolutely no idea where any of this leads us, but it's gotta mean something.

-seanlpuzzle

2. Getting the hang of it. Copper
Join Date
Jan 2005
Location
Posts
21

## what if...

instead of right to left it is up and down?
0110101101111010011110111

01101011
01111010
01111011
1

what would that be?

3. I had thought of that too, but it doesn't really look like promising in that direction:

Numbers: 107, 122, 123

ASCII: KZ{

4. Getting the hang of it. Copper
Join Date
Jan 2005
Location
Posts
21

## uh, i dont think so

after doing a "bit" of research, i discovered this

The first code is as follows
/
not a code
?

Mine are as follows
k
z
(

This might have been good...but?!

5. Getting the hang of it. Copper
Join Date
Jan 2005
Location
Posts
21

## i think

you are on the right track...but as the poem says...something is missing.

6. Needs to say Hello!
Join Date
Feb 2005
Posts
4

## KZ

For what its worth "KZ" blocks on page 63 are EXACTLY the same make and sit in opposing corners of the page. Are you sure the other character isn't a "U"?

7. Did you try a vernam cipher for the binary? http://www.pro-technix.com/informati...rnam_base.html

8. ## Re: Binary numbers on the grid...

Originally Posted by seanlpuzzle
Hi all,
Okay, I'm pretty sure I discovered something...

Take the grid given, and for every black square, count as '0'. Every colored square, count as '1'. Read from left to right, top to bottom and get:

0010111100111110001111111

Now, break this up into 8-bit binary numbers:

00101111
00111110
00111111
1

Yes, there is one leftover. This may relate to the part of the dream "one on ending"

Notice anything about the numbers? They're exactly 1 greater than the preceeding number: 47.. 48.. 49..

Not sure of the relevance, but In ASCII that would also convert to: / .. 0 .. 1 ..

Absolutely no idea where any of this leads us, but it's gotta mean something.

-seanlpuzzle
I just looked at this binary code and it looks interesting. But I do not see the 47, 48, 49 sequence. Could anyone fill me in?

00101111 = 63-16 = 47
00111110 = 63-1 = 62
00111111 = 63

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