I don't believe the needle has anything to do with it at all.
Dichotomy means dividing something into exactly 2 parts in which none of the members of one set are the same as any in the other set. It's probably just another way of saying the sequence is in two parts of 10 numbers each (like all the other chapters). It doesn't necessarily imply the members are opposites. the rest of this clue implies it is hinting at where to start for each of the sets.
It'd be great if tomorrow Ron announce there's a winner of chapter 4 and later say it's April's fool.
The town folk would gather with lit torches and rope.
As with most of the clues..and fitting with the chapter theme of "two", many of them have two meanings. I have not discovered them all...
Looking at the Valentines clue again.. This years valentines day is where it's at. Ok, 2014, on friday the 14th. The 14 appears twice, so obviously an extra hint to the 14th, which we have as J,L,N. You can take your guess of which of those three might be at 14, but what about the 20, in 2014?
Ok so margins won't space this well. Just take the capitals and line it up vertically on your own. A new line of thinking I am trying without using a simple skip. If you do it a couple times, you'll get the idea (and realise its not that hard)
yourfirststepmaybetoolaRgetotake,
asmallerstepyoumUstmake,
followtheRULEthrough,
tocompletEthisclue,
The dichotomy could be the husband and wife...which is my current interpretation, and has been repeated in other clues.
The sequence is ten numbers each, but two went on a hunt of their own, I'll assume one in each half of the puzzle. Then, I can't really explain 1-10, 11-20, 21-26 clue, plus equal halfs, but use all 26, plus rhombicuboctahedron, plus two on their own hunt. It doesn't work out so well no matter how you do it.
"Start at the Needle!"
The current clue is screaming about the Needle!
Caesar shift and if you count from last week's clue to this week's clue it screams Needle!
The ambiguous nature of "still need to home" is my biggest stumbling block. Even if you use the associated metaphor, you can map that metaphor to at least 3 or 4 different numeric progressions. Combine that with the 4 or 5 most probable ways of using 2, and you end up with 20 or so potential cipher methods.
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