Since the road to ring redemption is now closed, and the prizes have been apparently sold at a garage sale, I’ve decided to make public my solution to DAR. This will be a multi-part post. Because it’s graphic intensive, it may take me several days between postings. Please bear with me. I intend to reveal everything except the redemption instructions. You should have enough information by the time I’m done posting to figure out how to redeem a ring, but I’ll leave that to you.

Part 1: The key

As I stated in an earlier post, I noticed the groupings labeled “Group A”, and “Group B” that are shown in Illustration_2-1.

I used the logic that I wanted the right facing crescent to retain the value of 2, and the left facing crescent with a value of 3 as they do in the Base 5 numbering system. It then appeared that Group A was showing 4,5,6,and 7. With Group B showing 6,7,8, and 9. My logic broke down however, when I labeled the sideways bar as zero. The system I came up with, worked great on the upside down version of the sequence from page 2, but no matter how hard I tried, I couldn’t get it to work on the two lines from page 5. After many, many weeks of studying the symbols in the HCB, I came to the conclusion that many of those symbols were flipped or rotated. The sideways bar that I had labeled zero in my original post, was actually a one turned sideways.

This brings up an interesting question that you’re probably asking yourself right now. If that symbol can be rotated, why can’t the others. I just want you to know, that I didn’t design this puzzle, so I can’t speak about the thought processes that went into it’s creation. I will say, that when I’m done explaining what I’ve discovered, you’ll see that some of the symbols in the HCB are manipulated constantly, while some never are. More on that in a later installment.

Now that I had numbers assigned to the page 2 & 5 strings, the question was, what to do with them. The first thing I did, was to make the spreadsheet shown below thinking that certain combinations of numbers would allow me to spell something out.

I studied this for several days, but came away empty. It then occurred to me, that in the original Treasure Trove contest, the author eliminated the letter Q from the alphabet to make his 5X5 polybius square work, so I thought maybe he had gone the other direction in this contest, and added something to the alphabet. I then redid my spreadsheet so that it was 27 columns wide as depicted below.

Again, nothing jumped out at me. There is a sequence of symbols, and now numbers, on the bottom row of symbols from page 5 that I had always found interesting. I had a brief forum discussion about them one time where I stated that it looked to me like it could possibly be a double letter sequence from a word. If you look at the bottom row, you’ll notice the number sequence 934634639. To me, it seemed that 346, 346 had potential, as did 463, 463 to be double letters. I studied my 27 wide spreadsheet and found that if I were to do a one position caesar shift of the alphabet to the left, the 463 would then fall under the letter “E”.

I experimented with this for several days, and could make partial words here and there, but nothing complete. As I studied this spreadsheet one day, something really remarkable jumped out at me. Every number in the first column, when you add the digits of that number together and keep adding them together until you’ve reduced that number to a single digit, will always equal the number at the top of the column. Same with column 2, 3, 4, 5, 6, 7, 8, 9. Every number in the 10 column, including the 10 could be reduced to 1. Every number in the 11 column, including the 11 could be reduced to 2, etc, etc. As an experiment, I then folded my spreadsheet into 9 columns as depicted below.

This is the code for infinity. You can run this series of numbers out to infinity, add the numbers together and keep adding them together until you’ve reduced it to a single digit, and it will always equal the number at the top of the column. The instructions are found on page 3 of the BOS, first paragraph. “Threes be the kindes of spell herein. Evry one holds its owne effect as described. Sum do occur nearby the caster, sum at greate distance.” The object is to add the numbers together until you’ve reduced to a single digit, then choose one of the three letters associated with that column.

In the following two illustrations, I’ve eliminated all of the numbers except 1 thru 9 which are at the top of the alphabet illustration.

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