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Thread: DAR According to Mister_Gizmo Part 1

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    Default DAR According to Mister_Gizmo Part 1

    Since the road to ring redemption is now closed, and the prizes have been apparently sold at a garage sale, Iíve decided to make public my solution to DAR. This will be a multi-part post. Because itís graphic intensive, it may take me several days between postings. Please bear with me. I intend to reveal everything except the redemption instructions. You should have enough information by the time Iím done posting to figure out how to redeem a ring, but Iíll leave that to you.


    Part 1: The key

    As I stated in an earlier post, I noticed the groupings labeled ďGroup AĒ, and ďGroup BĒ that are shown in Illustration_2-1.



    I used the logic that I wanted the right facing crescent to retain the value of 2, and the left facing crescent with a value of 3 as they do in the Base 5 numbering system. It then appeared that Group A was showing 4,5,6,and 7. With Group B showing 6,7,8, and 9. My logic broke down however, when I labeled the sideways bar as zero. The system I came up with, worked great on the upside down version of the sequence from page 2, but no matter how hard I tried, I couldnít get it to work on the two lines from page 5. After many, many weeks of studying the symbols in the HCB, I came to the conclusion that many of those symbols were flipped or rotated. The sideways bar that I had labeled zero in my original post, was actually a one turned sideways.



    This brings up an interesting question that youíre probably asking yourself right now. If that symbol can be rotated, why canít the others. I just want you to know, that I didnít design this puzzle, so I canít speak about the thought processes that went into itís creation. I will say, that when Iím done explaining what Iíve discovered, youíll see that some of the symbols in the HCB are manipulated constantly, while some never are. More on that in a later installment.

    Now that I had numbers assigned to the page 2 & 5 strings, the question was, what to do with them. The first thing I did, was to make the spreadsheet shown below thinking that certain combinations of numbers would allow me to spell something out.



    I studied this for several days, but came away empty. It then occurred to me, that in the original Treasure Trove contest, the author eliminated the letter Q from the alphabet to make his 5X5 polybius square work, so I thought maybe he had gone the other direction in this contest, and added something to the alphabet. I then redid my spreadsheet so that it was 27 columns wide as depicted below.



    Again, nothing jumped out at me. There is a sequence of symbols, and now numbers, on the bottom row of symbols from page 5 that I had always found interesting. I had a brief forum discussion about them one time where I stated that it looked to me like it could possibly be a double letter sequence from a word. If you look at the bottom row, youíll notice the number sequence 934634639. To me, it seemed that 346, 346 had potential, as did 463, 463 to be double letters. I studied my 27 wide spreadsheet and found that if I were to do a one position caesar shift of the alphabet to the left, the 463 would then fall under the letter ďEĒ.



    I experimented with this for several days, and could make partial words here and there, but nothing complete. As I studied this spreadsheet one day, something really remarkable jumped out at me. Every number in the first column, when you add the digits of that number together and keep adding them together until youíve reduced that number to a single digit, will always equal the number at the top of the column. Same with column 2, 3, 4, 5, 6, 7, 8, 9. Every number in the 10 column, including the 10 could be reduced to 1. Every number in the 11 column, including the 11 could be reduced to 2, etc, etc. As an experiment, I then folded my spreadsheet into 9 columns as depicted below.



    This is the code for infinity. You can run this series of numbers out to infinity, add the numbers together and keep adding them together until youíve reduced it to a single digit, and it will always equal the number at the top of the column. The instructions are found on page 3 of the BOS, first paragraph. ďThrees be the kindes of spell herein. Evry one holds its owne effect as described. Sum do occur nearby the caster, sum at greate distance.Ē The object is to add the numbers together until youíve reduced to a single digit, then choose one of the three letters associated with that column.

    In the following two illustrations, Iíve eliminated all of the numbers except 1 thru 9 which are at the top of the alphabet illustration.




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    Chant spells
    Your fyre
    Will light?


    So we were supposed to set the dammed thing on fire all along???? HAHAHAHAHAHAHAHAHA!!!
    Visit my web site: http://christinkeck.webs.com
    CK or as they say in Spain, "Yes, What?"

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    Quote Originally Posted by shecrab View Post
    Chant spells
    Your fyre
    Will light?


    So we were supposed to set the dammed thing on fire all along???? HAHAHAHAHAHAHAHAHA!!!

    i felt like doing that a few times

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    Gizmo,

    I've not worked on Dar seriously, but I'm very, very impressed by what you have revealed so far.
    If you recognize my avatar or know about shard V or "RUN...STEAL", please pm or e-mail me re possible partnering.

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    I'm sorry, Gizmo, all joking aside...I see you did a tremendous amount of work, but exactly what is the solution here? The three meaningless lines you got out of it? (And this is not to denigrate your work, but they are meaningless--because they do not say anything useful.) Unless this is a prelude to something else, which you have not yet shown.

    And if you did solve the entire puzzle, then why didn't you send the solution to the bankruptcy trustee as a claim against the assets?

    I'm just a bit confused about all this here. It looks like you did something--but was it a solution? I really don't think it is.

    There's a lot of sorting. A lot of calculation. A lot of stuff that the average person could not have done in a million years or even thought of---and I doubt for that reason alone it is solved.

    Why would anyone in their right mind make a puzzle so insanely complex?
    Visit my web site: http://christinkeck.webs.com
    CK or as they say in Spain, "Yes, What?"

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    Default concerning part #1

    mr gizmo, concerning part #1,
    the page 2&5 mystery shapes, i seem to have missed something.
    im not understanding why, the bar, and the 5 sided symbol
    retain the same values, even though they have 2 separate
    orientations, and why do the teardrop,and triangle, symbols,
    have 2 different values, as they have 2 orientations also
    i can see the right facing,and left facing, cresent
    and the 6 sided symbols, would retain their value, since
    they have only one ordination

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    Default forgot the pic

    sorry

    mr gizmo, concerning part #1,
    the page 2&5 mystery shapes, i seem to have missed something.
    im not understanding why, the bar, and the 5 sided symbol
    retain the same values, even though they have 2 separate
    orientations, and why do the teardrop,and triangle, symbols,
    have 2 different values, as they have 2 orientations also
    i can see the right facing,and left facing, cresent
    and the 6 sided symbols, would retain their value, since
    they have only one ordination
    Attached Images

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    Wow, if this really how MS did the solution, he had to be truly out of his mind to believe that up to 100 people could independently figure this out. Gizmo, whether this is right or not, it is definitely ingenious. The book describes a solution where the symbols swirl and coalesce, and your solution would match that description. Your equating the statement about sum nearby the caster, and sum at greate distance is very clever.

    I follow where you are going with the value of each symbol, but out of curiosity, did you try to simply use the number of edges to determine the value? Since your method is to work from the outside in, your overall method would work regardless of the value, and since each reduced single digit could be one of 3 letters, and 5 out of 9 digits could potentially be vowels, it would seem that you could derive multiple solutions. I also still don't follow why you did the caesar shift. That dramatically affects the outcome of your solution. You did it based on a pattern that you made an assumption was a double letter, specifically, a double E. However, in your final solution, it isn't an E. I am not saying that it isn't ultimately correct, but it is WAY WAY arbitrary, and the first part of your solution about combining the solutions has a lot of textual support.

    Anyway, I know you mention that you have solved the redemption instructions, which would seem to indicate you have taken this all the way, which is awesome. However, it still kills me that there are some clearly non-random patterns in these symbols that you don't take into account into your solution. It makes me wonder if these symbols are dual use.

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    Good evening all. It has been quite some time and I am glad to see there are people still working on these puzzles. I would like to see some sort of solve just for closure even if I did not spend nearly as much time on this book as the first or that CJ's Blaine nightmare(and I type that with the utmost respect).

    I have always had a feeling that this piece of the book may be the simplest cipher to crack. I would venture to guess the symbols are identified by number of vetices, 1-6, with 1-4 of those having a partner. 1(teardrop) 2(crescent) 3(triangle) 4(skinny rectangle) 5(pentgon) 6(hexagon).

    A number of immediate concerns arise. Why do only 4 of the 10 symbols have partners? What do we do with the partners, use, discard, ect? Why are we dealing with 103 total symbols?(prime number)

    It may help to look at just this piece and brainstorm on possible decoding methods instead of doing a deep dive. I imagine we could crack this piece as a group relatively quickly.
    Logic will break your heart......

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