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Thread: Fun Logic Puzzle. 500T!

  1. #1
    cthree's Avatar
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    Default Fun Logic Puzzle. 500T!

    Not mine--a friend showed this to me:

    You have 12 statues. They are all beautiful but all the same. Same color, shape, style, EXACTLY the same. Except one statue is odd. It weighs EITHER more or less than the other 11 statues. You also possess a libra like scale like this one:



    You may use it 3 times. How do you discover the identity of the odd statue?

    You solution must work in the General case (meaning it works in all circumstances-you cant rely on setting lucky )

    Please use spoilers!

    First correct answer gets 500 T.

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    gabi's Avatar
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    the first step is give the statues numbers to know which one we are weighing, then
    if the plate on the left is lighter it will go up so that will be called U, if it is heavier it will go down and it will call that D and if both weight the same it will stay in the middle (M).
    Ok now if statue #1 is heavier than the rest
    if it is lighter than the rest then the
    In the next table we can see all the results depending on which statue is heavier or lighter

    You should notice that

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    sory about the messy format above

    fenix

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    It always helps to read the whole scenario. lol

    I will go back into hiding now.

    fenix

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    cthree's Avatar
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    gabi--very elegant reasoning. That is my favorite answer and you win the 500T congrats--

    there is another "weigh" to do it ( )

    250T to the person who can describe the non base 3 style solution (gabi you must be too smart so ur dq'd from this one )

    Hope it hurt at least a little bit to think on it.. :P

    Congrats! Good luck!!

    PS Fenix gets 100T just for randomly posting an answer without reading full disclosure--i do that all the time

  6. #6
    IwanttheHummingBird is offline Expert Twelever TwelevePlus
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    Cthree, what do you mean by non base 3 solution? ANyways, if only I was here sooner! I knew the answer!

    ~15


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    cthree's Avatar
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    Well, a better term to use is ternary.

    I'd like to see the non-ternary solution.


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    IwanttheHummingBird is offline Expert Twelever TwelevePlus
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    Well, I have another solution.



    Is that what you were looking for?



    ~IWTHB


  9. #9
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    No. Both you and Fenix assume that the odd statue is heavier. It can be heavier or lighter, so your methods do not work with three weighings.

    WHRECVBBLSMCEYVIHTEOIZROMR

  10. #10
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    Lol. I just saw this (been gone shooting my buddies' student film - capstone project all weekend.)

    Here goes, non base 3 (I think):



    Yours,
    Me[/spoiler]

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