I agree with turkeymonkey... we need to take a step backwards here. First of all, cartoonman, you'll see that I said that the triangle necessarily *can't* be equilateral if the H and W are the same. If the triangle theory is correct, the base would be naturally longer than the other two sides. (Oh and terabithan, you may certainly be right about the square being the right way to go, but clinging to that blindly is dangerous... let's open our eyes to other possibilities.)

Now, back to the beginning. This theory is based on the assumption that the "five to a side" clue and the "box as high as wide" clue are connected (which we don't know with certainty, of course). If it is a set of "boxes" in the shape of a triangle, it doesn't really matter if the boxes themselves are triangles, circles, squares, or pomegranites: you can still align them in such a way as to make a triangle as wide as it is high.

As for the the 322 representing the pythagoran theorem/triangles, my gut says that this is not the way to go... but who knows. Regardless, I like the way you're thinking hippodude... the one problem I have with your theory is that if each of those two right triangles contains 15 "boxes," then two of them placed together would give you 30. (Unless you overlapped the longer diagonal line, of course.)

Anyway, have I added anything with all this typing? Nope. Just wanted to try to get folks back on the same page with the triangle theory.

Matt

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